解决java获取访问用户的ip都是127.0.0.1
阿昌 Java小菜鸡
通过java代码去获取用户的访问ip,发现不管怎么获取都是`127.0.0.1`的ip ![在这里插入图片描述](https://img-blog.csdnimg.cn/50a12b7a2c2945f9bb00927f7b3b6480.png)

Java代码

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/**
* 阿昌
*/
public class IpAddressUtil {
/**
* 获取Ip地址
* @param request
* @return
*/
public static String getIpAddress(HttpServletRequest request) {
String ipAddress = null;
try {
ipAddress = request.getHeader("x-forwarded-for");
if (ipAddress == null || ipAddress.length() == 0
|| "unknown".equalsIgnoreCase(ipAddress)) {
ipAddress = request.getHeader("Proxy-Client-IP");
}
if (ipAddress == null || ipAddress.length() == 0
|| "unknown".equalsIgnoreCase(ipAddress)) {
ipAddress = request.getHeader("WL-Proxy-Client-IP");
}
if (ipAddress == null || ipAddress.length() == 0
|| "unknown".equalsIgnoreCase(ipAddress)) {
ipAddress = request.getRemoteAddr();
if (ipAddress.equals("127.0.0.1")) {
// 根据网卡取本机配置的IP
InetAddress inet = null;
try {
inet = InetAddress.getLocalHost();
} catch (UnknownHostException e) {
e.printStackTrace();
}
ipAddress = inet.getHostAddress();
}
}
// 对于通过多个代理的情况,第一个IP为客户端真实IP,多个IP按照','分割
if (ipAddress != null && ipAddress.length() > 15) { // "***.***.***.***".length()
// = 15
if (ipAddress.indexOf(",") > 0) {
ipAddress = ipAddress.substring(0, ipAddress.indexOf(","));
}
}
} catch (Exception e) {
ipAddress = "";
}
// ipAddress = this.getRequest().getRemoteAddr();

return ipAddress;
}
}

==突然想到项目是通过nginx做转发,如果nginx转发请求后未携带请求头,那就都是本地的127.0.0.1==
image

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#添加如下配置,让nginx转发时,携带请求头信息
proxy_set_header x-forwarded-for $remote_addr;

加入以上代码后,重新加载nginx配置文件,重新登录应该就可以了。

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./sbin/nginx -s reoload #重启nginx

再次查看解决问题!!!
image


 请作者喝咖啡